albino x regular sen.

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First, you do not get marbled convicts by crossing a regular with a pink. marbled are altogether another variant which has it's own set of genes. (Incomplete dominance, probably.)

If you crossed a normal senegalus with an albino, all of the babies would be normal, but carriers of the albino gene. If you crossed 2 of the babies to each other, you would get 25 percent normal, non carriers, 50 percent carriers, and 25 percent albino.
If you know about Punnett Squares, this is what this is.
A platinum is also another gene. But I'm not sure how that one works in fish. It's probably a genetic mutation that passed along to its babies.
 
Yep, listen to Santoury! The genes for albanism are recessive in all animals, so the characteristic wouldn't be apparent in the offspring.
 
Actually, it depends on the genetics. It would be as stated assuming the normal (wild type) is homozygous dominant. If the wild type is heterozygous than the babies will be 50% albino and 50% heterozygous.
 
reptileguy2727;1151566; said:
Actually, it depends on the genetics. It would be as stated assuming the normal (wild type) is homozygous dominant. If the wild type is heterozygous than the babies will be 50% albino and 50% heterozygous.

True, but it is unlikely that an albino survived to adulthood and bred in the wild to produce the heterozygous normal type dominant.
 
You don't have to have an albino to get a heterozygous individual. If that was the case you would not have any albinos. After all, all of the albinos in captivity came from wild caught (or descendants of wild caught) individuals (who were not albino). It is recessive, that means the gene can be there for many generations without ever occuring in a homozygous recessive individual that actually showed that recessive phenotype. And since the cross in question may involve captive bred individuals, it would not require a wild albino individual to have reproduced.
 
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