can anyone solve the third part of the problem... ive been working on it so many times and got it wrong -.- need help
need help from the MATH wizards
- Thread starter Ancient_Fish_Master
- Start date
((4a+4h)/(a+h-5)-((4a)/(a-5))
let x = 4a and y= a-5
now you have ((x+4h)/(y+h))-((x)/(y))
get a common denominator yields
(xy+4hy-xy-hx)/((y)(y+h)) = (4hy-hx)/((y)(y+h)) = h(4y-x)/((y)(y+h)
replace the variables x and y
and finish the work -> let me know if I made a mistake
let x = 4a and y= a-5
now you have ((x+4h)/(y+h))-((x)/(y))
get a common denominator yields
(xy+4hy-xy-hx)/((y)(y+h)) = (4hy-hx)/((y)(y+h)) = h(4y-x)/((y)(y+h)
replace the variables x and y
and finish the work -> let me know if I made a mistake
The book was wrong... The top should be -20, instead of 1. Pardon my chicken scratch hand writing.
not backwards...
I made it easier to solve (in my opinion) by replacing repeated information.
You start by making the problem simpler than once you have the final equation, you replace your variable with the correct values and finish the problem. I did the same thing you did except I showed every step...
I made it easier to solve (in my opinion) by replacing repeated information.
You start by making the problem simpler than once you have the final equation, you replace your variable with the correct values and finish the problem. I did the same thing you did except I showed every step...
How could you say you showed every step when you asked him to "replace the variable x and y and finish the work?"
Also, you forgot the 1/h from the original formula