NEED math hw please.

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Ancient_Fish_Master

Jack Dempsey
MFK Member
Jun 27, 2010
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Las Vegas
anyone can help me on this?

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I got that the smaller number is -4.8 and the larger is -1.6

I checked it, and it worked out.

The equations are: x+y=2(x-y) and y=2x+8

So what I did was substitue the y equation into the other equation:

x+(2x+8)=2[x-(2x+8)]
x+(2x+8)=2[x-2x-8]
x+(2x+8)=2x-4x-16
3x+8=-2x-16
5x+8=-16
5x=-24
x=-4.8

Then I substituted the value of x into the y equation:

y=2(-4.8)+8
y=-1.6

Then, to check my answer, I substituted both values into the original equation:

-4.8-1.6=2[-4.8-(-1.60)]
-6.4=2(-3.2)
-6.4=-6.4

Oh, and for my variables, x=smaller number, y=larger number
 
The smaller number could not possibly be 8... if you put 8 into the first equation, you get 2.6666... and for the second equation, you get 24...

Maybe the first equation should be y-x rather than x-y.....
 
Yes, it should be x+y=2(y-x). They should have specified that, but y=24

Lol, sorry for the confusion, but the smaller number is 8, the larger is 24. :grinno:
 
The smaller number could not possibly be 8... if you put 8 into the first equation, you get 2.6666... and for the second equation, you get 24...

Maybe the first equation should be y-x rather than x-y.....

This is it because you made y the larger number with the second equation, I missed it too the first time I checked your answer.
 
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