Ball Python Breeding?

[redtailcatfreak]

Alright thanks everyone. Yeah ive been just spacing out on this i dont know why.

I think you'll end up with more snakes that are already over abundant.....

Thanks for that useless imput.

You have "codominant" confused with "recessive". Codominant means that there are two dominant traits that can both be expressed at the same time (human blood type is a good example if you know anything about that). Recessive means that it is only expressed if dominant allele for that trait is there to overshadow it.

The way that chart shows it, the spider female is heterozygous dominant for the trait (meaning she has one allele for the spider trait and one for normal). In that case, 50% of the offspring will be spider, 50% normal. On the other hand, if she were homozygous dominant for spider, 100% of her offspring would also be spiders

Yeah my bad. Codoms is not something i want to get into right now. Haha need to get this down first.

At any rate the idea is not to breed normals with other morphs unless there is a market. I know there are markets for spiders, pastels, bumblebees, etc, but standard balls wholesale for, what, $5?

This is just my first time trying this out and i have a normal but really like the look of spiders so im just gonna give it a try. The norms wholsale for 15 and feeders 30 but im not really gonna try and sell them. This is just gonna be a personal hobby for now. As long as i can get something other than a norm out of it ill be happy. But alot of people buy norms because there so cheap.

 

[ozz465]

spider x norm = 50% spider, 50% norms , no hets with spiders .
a het pied x norm will get u norms t , slim chances there .
pieds are recessive so u need 2 with the gene to make more .

 

[redtailcatfreak]

spider x norm = 50% spider, 50% norms , no hets with spiders .
a het pied x norm will get u norms t , slim chances there .
pieds are recessive so u need 2 with the gene to make more .

Yeah that sucks cause i cant find and het pied females for a decent price. But who knows i might at the breeders expo. But our supplier for the store has het pied males for 50. oh well ill just try that later on.

 

[ozz465]

yea ive been checking prices as well , a het female baby is about $200 or so if u check around , breeder age females wont got less than $500 though.

 

[KittyKatFish100]

I just got a beautiful normal little female for $35. Normals are good for people who don't want/can't get expensive morphs but want more snakes. Sooo I think that the market for normals will always be there. Just my 2 cents...

 

[redtailcatfreak]

/\ yeah it always will be.

I just found a vendor whos gonna be at the Breeders expo and has late 10' male Spiders for $125. So ill prolly get one from him, they look nice. And i know someone else whos gonna be there and has breeder norm females for $50. But ill have to see the quality on those.

Oh and Someone came into the store yesterday and might be givin me a 3 1/2 foot ball. More than likely a norm but idk the sex. Still waiting for him to call. God i love workin at a petstore. Hahaha

 

[muffywrx]

You have "codominant" confused with "recessive". Codominant means that there are two dominant traits that can both be expressed at the same time (human blood type is a good example if you know anything about that). Recessive means that it is only expressed if dominant allele for that trait is there to overshadow it.

The way that chart shows it, the spider female is heterozygous dominant for the trait (meaning she has one allele for the spider trait and one for normal). In that case, 50% of the offspring will be spider, 50% normal. On the other hand, if she were homozygous dominant for spider, 100% of her offspring would also be spiders

However there are no homozygous forms of spider, as this is a lethal combo.

In addition, 50% would still be spiders because they are on different alleles.

 

[muffywrx]

normal x het recessive= 50% normal possible hets (chance of carrying recessive gene of choice)
het recessive x het recessive = 25% normal 50% het recessive 25% recessive (all normal looking babies are 66% possible het)
normal x recessive = 100% het (normal that carries recessive gene of choice)
recessive x recessive = 100% recessive
recessive1 x recessive2 = 100% normal het recessive 1&2
normal x codom = 50% normal 50% codom
codom x codom = 25% normal 50% codom 25% super (two copies of the codom gene)
codom1 x codom2 = 25% normal 25% codom1 25% codom2 25% codom1&2
dominant x normal = 50% normal 50% dominant
dominant x dominant = 75% dominant 25% normal (lethal in some combinations like spider)
dominant1 x dominant2 = 25% normal 25% dominant1 25% dominant2 25% dominant 1&2

Hope that helps.
http://www.worldofballpythons.com/wizard/

 

[Wiggles92]

/\ yeah it always will be.

I just found a vendor whos gonna be at the Breeders expo and has late 10' male Spiders for $125. So ill prolly get one from him, they look nice. And i know someone else whos gonna be there and has breeder norm females for $50. But ill have to see the quality on those.

Oh and Someone came into the store yesterday and might be givin me a 3 1/2 foot ball. More than likely a norm but idk the sex. Still waiting for him to call. God i love workin at a petstore. Hahaha

Based on the age of your current ball python, I'd say that you could hold off on getting a male until at least next year since it's better to wait until a female is two to three years old and of sufficient weight before attempting to breed her. You can usually find proven breeder males for pretty cheap and don't bother getting any normal males since you'll just be wasting your money. Also, it's always a good idea to grow out your own females in order to save some money and be assured of their health.

Now exactly how many female and mall ball pythons do you want to have at this point in time? I have a few suggestions for both the quantity department and the morph department, but I'd like to see what your goal is for this year and how much you are willing to spend.

Use the website that muffywrx suggested; it works great and can show you what you'd be looking at for possible offspring from pretty much any pairing.

 

[andyjs]

However there are no homozygous forms of spider, as this is a lethal combo.

In addition, 50% would still be spiders because they are on different alleles.

I figured as much since everything I saw only showed one allele for spider