con x pink con

[Bderick67]

At one point I had 3 pairs of cons 2 barred and one pink pair. One barred pair produced only barred fry. The pink pair produced only pink fry. The other barred pair produced a mix of both 20% being pink.

I also had the barred male(that would produce a mix) breed with the pink female. That produced a mix of 80% barred and 20% pink.

Not sure this info is of use, but I think it relates to what Modest man is stating.

 

[Modest_Man]

Yeah, that backs up what I was saying almost exactly.

The barred pair that threw only barred offspring the fish would either both be homozygous dominant (AA X AA producing all AA fry) or one was homozygous dominant and one was heterozygous (AA X Aa producing 50% AA and 50% Aa; all of which would appear barred).

The pinks are both homozygous recessive (aa) so they'd only produce pink fry (aa X aa = all aa; pink).

For the last barred pair both parents were heterozygous (Aa) so they'd produce 25% AA, 50% Aa, and 25% aa (visually you'd have 75% barred (the AA's and Aa's) and 25% pink (the aa's)).

For the barred male (who threw pinks) and pink female the male is heterozygous (Aa) and female is homozygous recessive (aa), theoretically you'd get 50% Aa (barred) and 50% aa (pink). Which doesn't really match your 80 to 20 ratio.

 

[franchise513]

No, the striped gene is dominant. Look up genetics and read up on dominant and recessive genes. In humans the colors blend because we have at least 8 genes that contribute to skin color, con coloring is not that complex I'm guessing. New patterns will be the results of mutations which happen by chance. I bred a pink male with a striped female and now I have hundreds of fish that are striped. If you breed the heterozygous fish back together you will get 25% pink. Note the definitions of genotype and phenotype.

GREAT INFO!!! I just learned this in biology and this guy knows what he is talking about

 

[Fry]

Happy Holiday everyone!

Thanks franchise513

Modest_Man, I suspect that the survival rate may not be as high for the pinks from the Aa and aa pair. The pink gene is after all recessive and who knows what that really entails besides coloring.

 

[Bderick67]

Yeah, that backs up what I was saying almost exactly.

The barred pair that threw only barred offspring the fish would either both be homozygous dominant (AA X AA producing all AA fry) or one was homozygous dominant and one was heterozygous (AA X Aa producing 50% AA and 50% Aa; all of which would appear barred).

The pinks are both homozygous recessive (aa) so they'd only produce pink fry (aa X aa = all aa; pink).

For the last barred pair both parents were heterozygous (Aa) so they'd produce 25% AA, 50% Aa, and 25% aa (visually you'd have 75% barred (the AA's and Aa's) and 25% pink (the aa's)).

For the barred male (who threw pinks) and pink female the male is heterozygous (Aa) and female is homozygous recessive (aa), theoretically you'd get 50% Aa (barred) and 50% aa (pink). Which doesn't really match your 80 to 20 ratio.

Yes I could be in error here, this was 4 years ago. Hard to count 1/4" fry to exact ratio, plus most were used as food before they even got to a 1/4".