Marbled Cray Breeding Help!

[Boboslunch]

Hi guys. I currently have 2 MKs in a 20g one that is more aggressive (tore most of the arms of the 3rd,k killing it) the other that almost never leaves its cave. Well I finally found 2x .5" babies thwo days ago. Just 2. It had to be the one that hides but how could there only be 2?
Does anyone struggle with cannibalism of fry? Would it be better if I removed the aggressor and just had the l adult female? I feed them enough, they always have anacharis to.snack on when its not dinner, plus there are snails in there too ,just incase they get hungry.

 

[fishhead0103666]

Well I can't help you with your questions but I figured you might be interested in knowing that marbled crayfish don't breed, they clone themselves.
Perhaps kno4te can help you.

 

[Boboslunch]

Well I can't help you with your questions but I figured you might be interested in knowing that marbled crayfish don't breed, they clone themselves.
Perhaps kno4te can help you.

Lol. My bad for not wording that right.
Trying to clone them sounded like i was doing it in a lab or something, and trying to get some Crays to parthonagenitically clone themselves to build a colony to feed my puffer was just a ton of words that didnt make any difference to the question I was asking. Plus when my two female crays produced on their own, after having them since .5", it atleast proved they were indeed Marmorkrebs. Either way, not a popular subject I guess. Spose Ill continue with trial and error.

 

[Fat Homer]

Do you have lots of cover for the crays and some moss like plants for the young to hide in???

However, to answer your question if not fed enough (and sometimes coz they just want to be SOB’s) they will cannibalize each other...

Larger tank + more decoration will likely give you better numbers and chances, better still if you can separate adults from young...

 

[Rob909]

Fat Homer beat me to it.
More food and hides is the perfect advice. I find that mine like to hide in ceramic rings as juveniles and pvc as adults.