Keeping fish and being Mathematically challenged

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It's pretty easy though, just had to refresh me memory a bit.

d/dL 1/2*L^2 + d/dL 1 + d/dL 1/2*L^2

d/dL 1/2*L^2 - Reduces to 2 * 1/2 = 1, L^1 = L
d/dL 1 - Reduces to 0 since derivative of a constant is 0
d/dL 1/2 L^2 - Same as the first, reduces to 2 * 1/2 = 1, L^1= L

Nerd alert lol
 
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It's pretty easy though, just had to refresh me memory a bit.



d/dL 1/2*L^2 - Reduces to 2 * 1/2 = 1, L^1 = L
d/dL 1 - Reduces to 0 since derivative of a constant is 0
d/dL 1/2 L^2 - Same as the first, reduces to 2 * 1/2 = 1, L^1= L

Nerd alert lol

Kewpie you're bragging again lol and I have no idea what on earth is going on there it's like gibberish to me lol
 
I actually speak Afrikaans, English is my second language so sometimes I still get something wrong with it.
Afrikaans is my 2nd.
Ek is nie die beste nie, maar ek kan 'n bietjie praat

Kom ons praat 'n hele klomp twak wat hulle nie verstaan nie :p
 
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