And it has Begun(muahahahaha)
- Thread starter AndrewMack
- Start date
Stop talking and post some pictures of your project progress please....
spiff;3215054; said:
*sigh* I'm assuming you didn't read the wiki? Let me help you out. Let's take this formula:
P = pgh
where,
- P is the hydrostatic pressure (Pa);
- ρ is the liquid density (kg/m3);
- g is gravitational acceleration (m/s2);
- h is the height of liquid above (m).
Now if we take that into consideration that means when choosing a glass piece that is properly braced on all sides with no deflection then length is no longer a factor.
Also I noticed in your statement that you say that for every extension of length there's more load applied to the center. Please explain this strange phenomenon because from what I understand in this extension of length the added load will be evenly distributed across this extended length and won't effect center of the tank at all.
Unless of coarse you meant to say height then that makes sense because that would increase the load at the center of the tank because it would have to support a greater amount of pressure because of the additional water placed on top of it.
brianhellno;3216742; said:*sigh* I'm assuming you didn't read the wiki? Let me help you out. Let's take this formula:
P = pgh
where,
Now notice in this equation the only requirement to calculate the fluids pressure is the height of the liquid. It doesn't matter with width or length because they don't add pressure.
- P is the hydrostatic pressure (Pa);
- ρ is the liquid density (kg/m3);
- g is gravitational acceleration (m/s2);
- h is the height of liquid above (m).
Now if we take that into consideration that means when choosing a glass piece that is properly braced on all sides with no deflection then length is no longer a factor.
Also I noticed in your statement that you say that for every extension of length there's more load applied to the center. Please explain this strange phenomenon because from what I understand in this extension of length the added load will be evenly distributed across this extended length and won't effect center of the tank at all.
Unless of coarse you meant to say height then that makes sense because that would increase the load at the center of the tank because it would have to support a greater amount of pressure because of the additional water placed on top of it.
P= hydrostatic pressure... is applied evenly, this means the center of the glass too, and I guess you think this formula means there is no load on the middle of the glass. Then why even go half inch, why don't you just count on your outstanding reason and go with quarter inch?
Twenty Four pages and the build is being re-done. Reminds me why i usually don't read these long threads. 
A mobile home has the main steel beams but also has steel girders sticking out every 4' or so on the sides, so going with an outside wall shouldn't be an issue.
I'm curious how your going to move this tank. In the service you might get another duty station or when you get out and you wanna move.
Good luck with the build and have fun when your doing it.
Thank your for your service.
A mobile home has the main steel beams but also has steel girders sticking out every 4' or so on the sides, so going with an outside wall shouldn't be an issue.
I'm curious how your going to move this tank. In the service you might get another duty station or when you get out and you wanna move.
Good luck with the build and have fun when your doing it.
Thank your for your service.
spiff;3217251; said:
I don't think you understand hydrostatic pressure yet. Let's break it down just a bit more.
Hydro = water
static = having no motion, being at rest
pressure = the effect that occurs when a force is applied to a surface.
So when we put it all together it's basically the amount of force water applies on a surface while at rest. When you say is applied evenly I hope your not referring to the pressure of the water being the same in the entire tank. Now as far as half way up the tank goes you would have half the pressure than at the bottom of the tank. Again regardless of length of the container the water is in.
Buddy, several people have tried explaining this to you. Maybe not in as much detail as I have but I don't know how to explain this differently. Are you a visual person? I could make a picture or something.
brianhellno;3218253; said:
I understand better than you, apparently. Its the same simple principle of the sides an acrylic aquarium bowing EVEN WHEN ITS SUPPORTED ON ALL FOUR SIDES. Guess what fixes this symptom?!?! Thicker acrylic. Gee whiz, that's so complicated. And yes, the longer the tank for the given thickness of acrylic, the worse the bowing would be. For glass, this translates to static load, or the minimizing of the safety factor.
are you ladies done yet? The bottom line here is that there isn't enough of an issue to worry about AND... for those who arn't paying attention... the tank size has shrunk again
spiff;3218400; said:
Appearently you do not. Based on Pascals law and Boyles law we can determine the ammount of pressure at a given depth of water. This pressure is always constant. This means that no matter the volume of water, as long as it's at rest it will always have the same pressure at depth as any other volume of water at the same depth. This of course assumes a few things such as pure water etc. A good way to look at this is to think of diving, the pressure on a diver is the same in a lake or the ocean (ignoring salt water). You can also think of it this way. It requires the same pressure to force air down into water no matter the volume of water. Length or volume do not affect pressure. Depth does.
